Y=-0.0027x^2+219.79x-4E+06

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Solution for Y=-0.0027x^2+219.79x-4E+06 equation:



=-0.0027Y^2+219.79Y-4+06
We move all terms to the left:
-(-0.0027Y^2+219.79Y-4+06)=0
We get rid of parentheses
0.0027Y^2-219.79Y+4-06=0
We add all the numbers together, and all the variables
0.0027Y^2-219.79Y-2=0
a = 0.0027; b = -219.79; c = -2;
Δ = b2-4ac
Δ = -219.792-4·0.0027·(-2)
Δ = 48307.6657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-219.79)-\sqrt{48307.6657}}{2*0.0027}=\frac{219.79-\sqrt{48307.6657}}{0.0054} $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-219.79)+\sqrt{48307.6657}}{2*0.0027}=\frac{219.79+\sqrt{48307.6657}}{0.0054} $

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